If A = , B = and C = , verify that (A – 2B) + 3C = A – (2B – 3C)
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Answer:
Given A=B=C=K
So
A=K
2B=2K
3C=3K
So we get
(k-2k)+3k=2k
RHS=k-(2k-3k)
k+k
2k
So LHS=RHS
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