Math, asked by raghavs3290, 3 days ago

If a, b and care positive integers less than 10 then the surn of three three-digit numbers,S = abc #bea+cab must be divisible by:​

Answers

Answered by gsai1595
0

Answer:

111

Step-by-step explanation:

S=abc+bca+cab

S=(100a+10b+c)+(100b+10c+a)+(100c+10a+b)

S=111a+111b+111c

S=111(a+b+c)

S must be divisible by 111

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