If a, b and care positive integers less than 10 then the surn of three three-digit numbers,S = abc #bea+cab must be divisible by:
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Answer:
111
Step-by-step explanation:
S=abc+bca+cab
S=(100a+10b+c)+(100b+10c+a)+(100c+10a+b)
S=111a+111b+111c
S=111(a+b+c)
S must be divisible by 111
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