Question

If A,B are acute angle such that A=cosB then A+B = not angles I am asking just A +B
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Answer 1

Answer:

In triangle ABC ,

Cos A = opposite side / hypo.

= AC / AB -1

Cos B = adjacent side / hypo.

= BC / AB -2

We gave cos A = cos B

Thus by 1 and 2,

AC / AB = BC / AB

Thus

AC . AB = BC . AB

AC = BC

thus AC and BC are two sides of triangle ABC

Thus angle A = angle B

( angles opposite to equal sides are equal )

This is the answer .

Hope it helps u .....

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Answer 2

Answer:

in triangle A B C,

Cos A= opposite side/hypo

=AC/AB=1