Math, asked by scs417115, 5 months ago

If A,B are acute angles such that sinA=cos B, then S+B= options : A) pi by 2. B) pi by 4. C) pi .D)pi by 3​

Answers

Answered by kaliswamys
2

Answer:

given SinA= CosB

Sin45=Cos45= 1/2

A= 45, B = 45

A+B =90 degree

= π/2

Answered by tennetiraj86
12

Step-by-step explanation:

Given that:-

Given that:-A,B are acute angles such that

sinA=cos B

sinA=cos B =>SinA=Sin(90-B)

sinA=cos B =>SinA=Sin(90-B)we know that CosA=Sin(90-A)

sinA=cos B =>SinA=Sin(90-B)we know that CosA=Sin(90-A)=>A=90-B

sinA=cos B =>SinA=Sin(90-B)we know that CosA=Sin(90-A)=>A=90-B=>A+B=90°

sinA=cos B =>SinA=Sin(90-B)we know that CosA=Sin(90-A)=>A=90-B=>A+B=90°=>A+B=180°/2

sinA=cos B =>SinA=Sin(90-B)we know that CosA=Sin(90-A)=>A=90-B=>A+B=90°=>A+B=180°/2=>A+B=π/2

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