If a,b are complementary angles , sina=3/5, then cosacosb-sinasinb=
Answers
Answered by
1
Step-by-step explanation:
cos a = 2 / 5
cosb = 3 /5
sinb = 1 as b = 90
cosacosb - sina sinb
2/5 × 3/5 - 3/5 ×1
6/5 - 3/5
=3/5
Answered by
3
Answer:
Step-by-step explanation:
as the angles are complementary
a+b=90
given
sina=3/5
cosa=4/5 as sin square a +cos square a is one
sinb =sin(90-a)=cosa=4/5
cosb=cos(90-a)=sina=3/5
then we get
cosacosb-sinasinb=4/5*3/5-3/5*4/5
=12/5-12/5=0
hence zero is answer
Similar questions