If A,B are non-empty sets then (A-B)union (B-A) equal
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Let x be any arbitrary element of (A-B) U (B-A).
Then,
=> x ∈ A-B OR x ∈ (B-A or x ∈ A)
=> (x ∈ A or B) OR (X ∉ B or x E/ A)
=> x ∈ (A U B ) - ( A ∩ B)
Thus,
( A - B) U (B - A) ⊆ ( A U B) - (A ∩ B)
Now,
Let y be an arbitrary element of (A U B ) - ( A ∩ B.
Then, y ∈ (A U B ) - ( A ∩ B)
y ∈ (A U B ) and y ∉ ( A ∩ B)
y ∈ A or y ∈ B) and (y ∉ A or y ∉ B)
y ∈ A or y ∉ B) and (y ∈ B or y ∉ A)
y ∈ (A - B) U (B - A )
Thus,
(A - B ) - ( A ∩ B) ⊆ (A - B ) U ( B - A )
Hence, (A U B ) - ( A ∩ B ) = (A - B ) U ( B - A)
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