Math, asked by Anonymous, 10 months ago

If a,b are positive real numbers such that a−b=2, then find the smallest value of the constant L for which \sqrt{x^2+ax} - \sqrt{x^2+bx}
<1 for all x>0.​

Answers

Answered by Anonymous
2

here is ur answer in attachment

hope it helps U

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Answered by Chaitanyahere
3

Arey bolat ka nahi tu Dual nahi ahe ka ....

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