If a,b are positive real numbers such that a−b=2, then find the smallest value of the constant L for which
- ![\sqrt{x^2+bx} \sqrt{x^2+bx}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2%2Bbx%7D)
<1 for all x>0.
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here is ur answer in attachment✌
hope it helps U ✔
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Arey bolat ka nahi tu Dual nahi ahe ka ....
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