If a, b are root of ax square+ bx+ b= 0,then root a ÷ b+ root b÷ a+ root b÷a is
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ax
2
−bx+1=0hasimaginaryroots
∴D<0
b
2
−4a<0
b
2
<4a
leb
2
<4a
∴a>0
∴f(x)>0for∀x∈R
∴f(−1)=a+b+1>0
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