If a,b are roots of x2+px+1=0 c,d are roots of x2+qx+1=0 then (a-c)(b-c)(a+d)(b+d)
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Answer:
let the a be the alfa and the b be the beta
now given equation is x²+qx+1=o
comparing the given equation with ax²+bx+c=0
we get,
a=1,b=1,c=1
now,
Alfa+beta= -b/a
= -1/1
=1
now,
alfa×beta=c/a
=1/1
=1
ans_a and b are the roots of given equation
Answered by
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Answer:
q2-p2
Step-by-step explanation: Attached Below
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