Question

If a,b are supplementary angled then

${ \cos}^{2}a + \sin ^{2} b =$
Note:

No spams❌❌

answer ASAP✌❤

Explaination needed ✅✅✅​

Answer 1

since a and b are supplementary a+b=180

a=180-b

Substituting the values

==> sin^2(180-b)+ cos^2(b) (also sin (180-a)=sin(a))

==> sin^2(b)+cos^2(b)

==> 1.

HOPE IT HELPS

Answer 2

$\mathfrak{\underline{\underline{Answer:-}}}$

cos²a + sin²b = 1

$\mathfrak{\underline{\underline{Explanation:-}}}$

Given,

a,b are supplymentary angles

So,

a+b = 180•

a = 180-b

Now,

cos a = cos(180-b)

cos a = cos b

cos²a = cos²b

Therefore,

cos²a + sin²b = cos²b+sin²b

$\boxed{{cos}^{2}Φ + {sin}^{2}Φ= 1}$

Hence,

cos²a +sin²b = 1