Question

If a,b are the distinct roots of the equation x^2-x+1, then a^101+b^107 is equal to

Answer 1

look here basically I m straight away tried

with assumptions

Try with values of w

u get a=-w

b=-w^2

-w^101+(-w^214)

=-w^2+-w

=-(w^2+w)

=-(-1)

=1

Answer 2

Step-by-step explanation:

above answers is correct but it was e is purely correct