Question

if a,B are the roots of 9×2+6×+1=0, the equation with the roots 1/a,1/B is a)2×2+3×+8=0 b)×2+6×-9=0 c)×2+6×+9=0 d)×2-6×+9=0​

Answer 1

Answer:

The answer is a option B

Answer 2

$9x² + 6x + 1 = 0$

$alpha + beta = \frac{-6}{9}= \frac{-2}{3}$

$alpha*beta = \frac{1}{9}$

Now , The eq. whose zeroes are 1/alpha & 1/beta are -

x²-(1/alpha + 1/beta)x + 1/(alpha*beta)=0

x² - (-2/3)/(1/9)x + 1/(1/9) = 0

x² + (2/3 * 9)x + 9 = 0

x² + 6x + 9 = 0