Question

if a,b are the roots of a quadratic equation x² + x + 1, then 1/a + 1/b ​

Answer 1

Answer:

a+ b = -1( Sum of roots is equal to -b(coefficient of x)/a(coefficient of x^2)

a× b = 1( product of zeores is equal to c(constant)/a)

so 1/a + 1/b = (a+b)/ab( by taking LCM)

= -1/1

= -1

Answer 2

Answer:

1/a + 1/b = -1

Step-by-step explanation:

The standard form of aquadratic eqn is Ax² + Bx + C = 0

and sum of its roots= -B/A

Product of its roots = C/A

In x² + x + 1, A=1, B=1 & C=1

sum of the roots=a+b= -B/A

a+b= -1/1 = -1

Product of its roots = ab = C/A

ab = 1/1 = 1

Now, 1/a + 1/b = (a+b)/ab .....(taking LCM)

= (-1)/1 = -1

1/a + 1/b = -1