Question

if a, b are the roots of polynomial 3x²-11x-3, then ab=?​

Answer 1

Step-by-step explanation:

$3 {x}^{2} - 11x - 3 = 0$

$by \: formula \: method$

$x = \frac{ 11 \pm \sqrt{121 - 4(3)( - 3)} }{6}$

$x = \frac{11 \pm \sqrt{121 + 36} }{6}$

$x = \frac{11 \pm \sqrt{157} }{6}$

Answer 2

Answer:

-1

Step-by-step explanation:

here a=(11+root157)/6

and b=(11-root157)/6

therefore ab=-1