Question

If a,B are the roots of the equation ax? + bx + c = 0, then the quadratic equation whose roots
a.+B, aß is
a) a?x? + a(b - c)X + bc = 0
b) a? x2 + a(b-c) x-bc = 0
c) ax? + (6 + c)X + bc = 0
d) ax? - (b + c)x - bc = 0​

Answer 1

The given AP is     5,412,4,312,3……..

The first term = 5,

common difference = (412−5)=(92−5)=−12

∴ a = 5, d = −12

The nth term is given by

Tn = a + (n-1) d

T14 = 5 + (25 – 1) (-1/2) = 5- 12 = -7

Hence the 25th term is – 7

Answer 2

Step-by-step explanation:

if the roots of the equation ax