Math, asked by shubham6198, 1 year ago

if a, b are the roots of the equation x^2-2x+2=0 then the value of a^2+b^2

Answers

Answered by tejasri2
1
a and b are roots then a²+b² = (a+b)²-2ab
= (-b/a)²-2(c/a)
= (--2)²-2(2)
=4-4 = 0

here is ur answer
Answered by jaya1012
0
HELLO.......FRIEND!!

THE ANSWER IS HERE,

the \: roots \: of  \: the \: equation \: are \: a \: and \: b.

 =  >  \:  {a}^{2}  +  {b}^{2}  =  {(a + b)}^{2}  - 2ab


 =  >  \: a + b =  \frac{ - coefficient \: of \: x}{coefficient \: of \:  {x}^{2} }

 =  >  \: a + b \:  = 2

 =  >  \: ab =  \frac{constant}{coefficient \: of \:  {x}^{2} }

 =  >  \: ab = 2

 =  >  \:  {a}^{2}  +  {b}^{2}  =  {2}^{2}  - 2(2)

 =  >  \: 4 - 4

 =  >  \: 0


:-)Hope it helps u.
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