Question

if a,b are the roots of the equation x square plus kx plus 12 is equal to 0 such that a-b=1 find k​

Answer 1

k = ±7

x²+kx+12 = 0

Sum of roots (a+b) = $- \frac{k}{1} = - k$

Product of roots (a×b) = $\frac{12}{1} = 12$

Now, (a-b)² = (a+b)² - 4ab

(1)² = (-k)² -4(12)

1 = k²-48

k² = 49

k = ±7