Math, asked by TenderJr, 6 months ago

If a,b are the roots of the quadratic equation x^2+x+1=0 then find the value of 1/a+1/b​

Answers

Answered by tejoshnandachilakala
1

Answer:

-1

Step-by-step explanation:

Let a,b be the roots of this quadratic eq.

∴Sum of roots:-(a+b)=-b/a

∴Product of roots:-(ab)=c/a

In the quadratic eq:-x^{2} +x+1=0

a+b=-1/1=-1

ab=1/1=1

\frac{1}{a} +\frac{1}{b}\\= \frac{a+b}{ab} \\=\frac{-1}{1}

=-1

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