Question

If a,b,are the zeroes of the polynomial AX2+bX+C then (a2+b2)=?


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Answer 1

Answer:

(B^2 - 2AC)/A^2

Step-by-step explanation:

a, b are two zeroes.

According to Vieta's formula,

Sum of roots = a + b = -B/A

Product of roots = ab = C/A

a^2 + b^2 = (a+b)^2 - 2ab = (-B/A)^2 - 2(C/A) = (B^2 - 2AC)/A^2