Question

If a, b are the zeroes of the polynomial p(x)= x-px-(p + c), then find the value of (a +1) (B + 1)​

Answer 1

Answer:

We have,

f(x)=x

2

−p(x+1)−c=0

f(x)=x

2

−px−(p+c)=0 .............(1)

Since,

α,β are the zeroes of the above polynomial.

So,

α+β=p

αβ=−(p+c)

Since,

(α+1)(β+1)=0

αβ+α+β+1=0

−p−c+p+1=0

−c+1=0

c=1

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