Question

if a,b are the zeroes of the polynomial x^2-16 then ab(a+b)is
a)o
b)4
c)-4
d)16​

Answer 1

Answer:

Step-by-step explanation:

Value of “ αβ(α + β) = 0 ”.

Step-by-step explanation:

★ Given that :

α and β are the zeroes of the Quadratic Polynomial p(x) = x² - 16.

★ To find :

Value of αβ(α+ β) .

★ Let :

◼ According to the general form of Quadratic Polynomial is : “ ax² + bx + c = 0 ”.

◼ Consider the given polynomial.

a = 1

b = 0

c = - 16

★  Now

:➡ Sum of the zeroes : α + β = -b/a = -0/1 = 0

➡ Product of the zeroes : αβ = c/a = -16/1 = - 16

Now,we can find out the value of αβ(α+ β) .

➠ 0(-16)

➠ 0

∴ Value of αβ(α+ β) = 0

Followw me

thanks

@Jiyaa021

Answer 2

Answer:

0 is the correct option

Step-by-step explanation:

a- 1

b--0

c_-16

-B/ a-- 0/1

C/ a_-16/1

alphabita ( alpha+ bita )

0(-16)

0