Question

if a,b are the zeroes of the polynomial x^2-(k+6)x+2(2k+1). Find k if a+b=1/2ab

Answer 1

Answer :

Step-by-step explanation:

x^2-(k+6)x+2(2k+1)

=>x^2 -kx +6x +4k+2

a+b=1/2ab

a+b= -((-k+6)/1)

=>a+b=k+6

ab= 4k-2/1

=>ab= 4k-2

=>a+b= 4k-2/2

=>a+b=2k-1

k+6= 2k-1

=>6+1=2k-k

=>k=7