Question

If a,b are the zeroes of the polynomial x²+ax-b be reciprocal of of each other,then b is equal to

Answer 1

Answer:B = 1

Step-by-step explanation: When two zeroes are the reciprocal of each other, then the product of those zeroes, that is 'c/a' because:

the zeroes are 'a' and 'b' and they are the reciprocal of each other so,

I can write 'a' and 'b' as 'a' and '1/a' (reciprocal)

so the the product is a*1/a which 1, therefore c/a which is the product will be one. If c/a = 1, then I can write that c =a because taking 'a' to the RHS will a*1 which is 'a'. So, c =a.

that implies that:  'c' term  = 'a' term  (by 'a' term I mean the coeffecient, 'c' is a constant.)

so b = 'a' term = coeffecient of x²

so b = 1