Question

If a , B are the zeroes of the quadratic polynomial x² - 7x+10, find the value of a3 +B3​

Answer 1

Answer:

133

Step-by-step explanation:

${x}^{2} - 7x + 10 = 0 \\ \\ \alpha + \beta = 7 \\ \\ \alpha \beta = 10 \\ \\ { \alpha }^{3} + { \beta }^{3} = ( \alpha + \beta )( { \alpha }^{2} - \alpha \beta + { \beta }^{2} ) \\ \\ = 7( {( \alpha + \beta) }^{2} - 3 \alpha \beta ) \\ \\ = 7(49 - 3 \times 10) \\ \\ = 7(49 - 30) \\ \\ = 7 \times 19 \\ \\ = 133.$