Question

If a, b are the zeros of the polynomial p(x) = x2 - p(x + 1) - c then (a + 1) (b + 1) = ?

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$let \: ax {}^{2} + bx + c \: is \: a \: quadratic \: equation \: \: and \: \: \alpha \: and \: \beta \: are \: zeroes$

$then \\ \\ \alpha + \beta = \frac{ - b}{a}$

$\alpha \beta = \frac{c}{a}$

$in \: the \: given \: equation$

$x {}^{2} - p(x + 1) - c$

$x {}^{2} - px - (p + c)$

$\alpha + \beta = \frac{ - (- p)}{ - (p + c)}$