If a,b are the zeros of the polynomial x2 + 8x + 6 frame a Quadratic whose zeros are
a) 1/a +1/b b) a/b+1 and b/a+1
Answers
Answered by
1
Answer:
x
2
+8x+6=0
Sum =α+β=−8
Product =αβ=6
Now equation whose zeroes are
α
1
and
β
1
is (x−
α
1
)(x−
β
1
)
x
2
–x(
α
1
+
β
1
)+
αβ
1
=x
2
–x(
αβ
α+β
)+
αβ
1
=x
2
–x(
6
−8
)+
6
1
=x
2
+
3
4x
+
6
1
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