if a, b are zeroes of a quadratic polynomial (ax²-6x-6) is 4,then find value of a
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Step-by-step explanation:
The given polynomial is
ax2 - 6x - 6
If a polynomial is given as ax2 + bx + c , then the sum of zeroes is -b/a and the product of zeroes is c/a.
It is given that the product of zeroes the given polynomial is 4.
product of zeroes = -6/a
4 = -6/a
a = -6/4
a = -1.5
The value of a is -1.5.
The sum of its zeroes is
sum of its zeroes = -(-6) / (-1.5) = -4
Therefore the sum of its zeroes is -4.
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