Math, asked by tandelparth200, 4 months ago

if a, b are zeroes of a quadratic polynomial (ax²-6x-6) is 4,then find value of a​

Answers

Answered by mailmesakthiv
0

Answer:

Step-by-step explanation:

The given polynomial is

ax2 - 6x - 6

If a polynomial is given as ax2 + bx + c , then the sum of zeroes is -b/a and the product of zeroes is c/a.

It is given that the product of zeroes the given polynomial is 4.

product of zeroes =  -6/a

4 = -6/a

a = -6/4

a = -1.5  

The value of a is -1.5.

The sum of its zeroes is

sum of its zeroes = -(-6) / (-1.5) = -4

Therefore the sum of its zeroes is -4.

Similar questions