Question

If a, b are zeros of p(x) = x2

– x – 4. Then find the value of one upon a and one upon b

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Answer 1

${\huge{\underbrace{\rm{Question~:}}}}$

★ If ‘a’ and ‘b’ are the zeroes of P(x) = x² - x - 4 .

Find the value of $\dfrac{1}{a}$ +$\dfrac{1}{b}$

${\huge{\underbrace{\rm{Answer\checkmark}}}}$

$\rm \: p(x) = {x}^{2} - x - 4$

→ Sum of zeroes (a+b) = $\dfrac{-(-1)}{1} = 1$

→ Product of zeroes (a.b) = $\dfrac{-4}{1}=-4$

$\rm \: now$

$\rm \mapsto \: \frac{1}{a} + \frac{1}{b} \\ \\ \mapsto \: \rm\frac{a + b}{ab}$

Just put the values !

$\mapsto \rm \: \frac{1}{ - 4} \\ \\ \mapsto \boxed{ \frac{ - 1}{4}}$