Math, asked by dinmacworld, 11 hours ago

If a+b/b = 3/2 and c/b-c 4/5, what is c-a/c?

Answers

Answered by phsz071nh
2

Answer:

c-a/c =3-5/2

Step-by-step explanation:

a+b/b-c=3/-5

b/c=c/b

c/b=4/2=2(2×2)

c-a=3-5

c=2

c-a/c =3-5/2

Answered by Anonymous
3

Given - a+b/b = 3/2 and c/b-c = 4/5

Find - c-a/c

Solution - Let us name the equation a+b/b = 3/2 to be equation 1 and the equation c/b-c = 4/5 to be equation 2

Solving the equation 1, we get -

2(a+b) = 3b

2a + 2b = 3b

2a = b

a = b/2

Solving equation 2, we get -

5c = 4(b - c)

5c = 4b - 4c

9c = 4b

b = 9c/4

b = 2.25c

Now, keeping the value of b in solution of equation 1, to find value of a

a = 2.25c/2

a = 1.13c

Keeping the value of a in c-a/c, to find the value of expression -

c-a/c

c - 1.13c/c

-0.13c/c

-0.13

So, value of c-a/c = -0.13

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