Math, asked by arun4669, 10 months ago

if a/b + b/a = -1 (a≠0 b≠0) then the value of a³-b³ is

Answers

Answered by ankitsharma7734
12

Answer:

a³-b³ = 0

Step-by-step explanation:

a/b + b/a = -1

(a^2 + b^2)/ab = -1

(a^2 + b^2) = -ab

a^2 + b^2 + ab = 0

we know that x^3- y^3 = (x-y)(x^2 +xy + y^2)

so,

a³-b³ = (a-b)(a^2 + b^2 + ab)

a³-b³ = 0 * (a-b)= 0

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