Question

If a/b+b/a=1 [a and b aren't equal to 0] then the value of a ​3_ b ​3 ​is?

Answer 1

a/b+b/a=1
⇒a^2+b^2-ab=0
Now,
a^3+b^3=(a+b)(a^2+b^2-ab)=(a+b)*0=0
a^3=-b^3⇒a=-b
hence a^3-b^3=2a^3