if a/b+b/a= -1 , prove that a^3-b^3=0
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here's the answer..................
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a/b+b/a=-1
a^2+b^2/ab=-1
a^2 + b^2 = -ab. ............1
now a^3 - b^3
(a-b)(a^2+b^2+ab)
(a-b)(-ab+ab).........from1
(a-b)0
0
Therefore it is proved that a^3-b^3=0
hope u find it helpful..
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