if a/b+b/a=_1 than (a³_b³)=?
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Given a/b + b/a = 1
(a^2 + b^2)/ab = 1.
a^2 + b^2 = ab --- (1)
Then a^3 + b^3 = (a + b)(a^2 + b^2 - ab)
= (a + b)(ab - ab) (From (1))
= 0.
Hope this helps! :)
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