If a/b+b/a=1,then a3-b3=
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Answered by
2
Answer: 0
Step-by-step explanation:A/b + b/a = 1
=> making denominator equal
=> (a²+b²)/ab = 1
=> a²+b² = ab
we know that , a³+b³ = (a+b)(a²+b²-ab)
=> a³+b³= (a+b)(ab-ab)
(as , a²+b² = ab)
=> a³+ b³ = (a+b)(0) = 0
the answer is 0
hope this helps
Answered by
0
Answer: 0
Step-by-step explanation:A/b + b/a = 1
=> making denominator equal
=> (a²+b²)/ab = 1
=> a²+b² = ab
we know that , a³+b³ = (a+b)(a²+b²-ab)
=> a³+b³= (a+b)(ab-ab)
(as , a²+b² = ab)
=> a³+ b³ = (a+b)(0) = 0
the answer is 0
hope this helps
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