If a/b+b/a=1, then find a^3+b^3.
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Step-by-step explanation:
A/b + b/a = 1
=> making denominator equal
=> (a²+b²)/ab = 1
=> a²+b² = ab
we know that , a³+b³ = (a+b)(a²+b²-ab)
=> a³+b³= (a+b)(ab-ab)
(as , a²+b² = ab)
=> a³+ b³ = (a+b)(0) = 0
the answer is 0
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