if a^b=b^a then prove (a/b)^(a/b)=a^{(a/b)-2}
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>>If A and B are sets, then p...
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If A and B are sets, then prove that A - B, A∩B and B - A are pair wise disjoint.
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Given:-A&B are two sets.
Pair wise disjoint means no two elements of any two sets are equal.
So,we have to proof:
(A−B)∩(B−A)=(A−B)∩(A∩B)=
(B−A)∩(A∩B)=ϕ
Letxϵ(A−B)∩(B−A)
∴xϵ(A−B)&xϵ(B−A)
xϵA−(i)orx∈
/
B−(ii)
xϵB−(iii)orx∈
/
A−(iv)
from(i)&(iv) we are at contradiction
Hence (A−B)∩(B−A)=ϕ
Now,let ∴xϵ(A−B)∩(A∩B)
xϵAorx∈
/
B
xϵAorxϵB
So,xϵAorxϵBorx∈
/
B
So,xϵBorx∈
/
B are at conradiction.
(A−B)∩(A∩B)=ϕ
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