Question

if a^b=b^a then the value of (a/b)^a/b-a^a/b-1 reduces to

Answer 1

Answer:

0

Step-by-step explanation:

a^b = b^a = k

so a = k^1/b, b= k^1/a

k^1/b = k^1/a

1/b = 1/a

a=b

a/b = 1

(a/b)^a/b - a^(a/b-1) = (1)^1 - a^(1-1)

= 1 - a^0

= 1 - 1

= 0

Answer 2

Answer:

a^b=b^a

Step-by-step explanation:

(a/b)^a/b-a^a/b-1