if a/b+b/c=1 then a³+b³=?
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Given, a/b+b/a=1
Or, (a^2+b^2)/ab=1
Or, a^2+b^2=ab
Or, a^2+b^2-ab=0
Now, a^3+b^3
=(a+b)(a^2-ab+b^2)
=0[as, one of these factors i.e. (a^2+b^2-ab=0)]
Or you may solve like :
a3+b3= (a+b) (a2-ab+b2)
Now a/b+ b/a=( a2+ b2)/ab =1
So a2 +b2=ab
so a2-ab+b2=0
So a3 +b3= 0
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