Math, asked by chinmaybhagwat22, 3 months ago

If (a-b)(b-c)/(a-c) = 1 and b=1, then which of the
following cannot be the value of a?
a) 0, b) 1, c) 2, d) 3, e) 4​

Answers

Answered by baranawalgaurav896
0

Answer:

e divided between Tyson and Tucker in the ratio 2:3.

\sf Sum \: of \: the \: Ratio \: = \: 2 \: + \: 3 \: = \: 5.SumoftheRatio=2+3=5.

\sf Tyson\: (pens)\: =Tyson(pens)=

\sf \dfrac{2}{5} \: * \: 60 \:= \: 2 \: * \: 12 \: = \: 24.

5

2

∗60=2∗12=24.

\boxed{\sf Tyson \: gets \: 24 \: pens.}

Tysongets24pens.

\sf Tucker \: (pens) \: =Tucker(pens)=

\sf \dfrac{3}{5} \: * \: 60 \:= \: 3 \: * \: 12 \: = \: 36.

5

3

∗60=3∗12=36.

\boxed{\sf Tucker \: gets \: 36 \: pens.}

Tuckergets36pens.

\textsf{If the ratios are reversed then,}If the ratios are reversed then,

\textsf{Number of pens of Tucker will become Tyson and Tyson will become Tucker.}Number of pens of Tucker will become Tyson and Tyson will become Tucker.

\textsf{After ratios are reversed, Tyson (pens) = 36 and Tucker (pens) = 24.}After ratios are reversed, Tyson (pens) = 36 and Tucker (pens) = 24.

\textsf{Number of pens Tyson will get more =}Number of pens Tyson will get more =

\sf 36 \: - \: 2436−24

\boxed{\sf 12 \: pens.}

12pens.

\huge{\bf{\red{\mathfrak{Conclusion:-}}}}Conclu

Answered by gurpreetlub2004
0
may be the answer is e)4
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