Question

if a/b =b/c and a,b,c>0 then show that, 1) (a+b+c) (b-c) = ab-c²
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Answer 1

Answer:

by normal mult we get (a+b+c) (b-c) = ab-ac+b²-c²

but we know a/b =b/c so b²=ac

(a+b+c) (b-c) = ab-(b²)+b²-c²

(a+b+c) (b-c) = ab-c²

hence proved

Answer 2

Answer:

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