Question

If a/b = b/c and a, b, c > 0 then show that, (a+b+c) (b-c) = ab-c²

Answer 1

Hey!!!...Here is ur answer

a/b=b/c

=> b^2=ac

Now,

(a+b+c)(b-c)

=> ab-ac+b^2-bc+bc-c^2

=> ab-ac+b^2-c^2

=> ab-ac+ac-c^2

=> ab-c^2

Hence Proved

Hope it will help you