If (a+b):(b+c):(c+a)=6:7:8 and (a+b+c)=14, then find c
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0
Answer:
Step-by-step explanation:
a=14/3 ,b=10/3 and c=6
Answered by
1
Answer:
the answer is C=6
Step-by-step explanation:
suppose (a+b) =6k
(b+c)=7k
(c+a)= 8k ( K is non zero quantity)by adding the three equation we get
2(a+b+c)= 21k
(a+b+c)= 21/2 ×k
a+b+c = 14
that's
21/2 ×k = 14
k=4/3
we know that
b+c= 7k
c+a=8k
from those equation we get that
c=(28/3)-b =(32/3)-a
from solving those equation we get
a-b= 4÷3=k
now a+b =6k
a+b=6(a-b)
a=7b/5
now a+b+c=14
put a=7b/5
7b/5 + b+c= 14
solving this equation we get
7b+5(b+c)=70
put b+c=7k=140/3
solve the eq. and get b=10/3
now b+c=7×4/3
c=28/3-b
=28/3-10/3
=18/3
=6
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