Question

If (a+b):(b+c):(c+a)=6:7:8 and (a+b+c)=14, then find c

Answer 1

Answer:

Step-by-step explanation:

a=14/3 ,b=10/3 and c=6

Answer 2

Answer:

the answer is C=6

Step-by-step explanation:

suppose (a+b) =6k

(b+c)=7k

(c+a)= 8k ( K is non zero quantity)by adding the three equation we get

2(a+b+c)= 21k

(a+b+c)= 21/2 ×k

a+b+c = 14

that's

21/2 ×k = 14

k=4/3

we know that

b+c= 7k

c+a=8k

from those equation we get that

c=(28/3)-b =(32/3)-a

from solving those equation we get

a-b= 4÷3=k

now a+b =6k

a+b=6(a-b)

a=7b/5

now a+b+c=14

put a=7b/5

7b/5 + b+c= 14

solving this equation we get

7b+5(b+c)=70

put b+c=7k=140/3

solve the eq. and get b=10/3

now b+c=7×4/3

c=28/3-b

=28/3-10/3

=18/3

=6