Question

If (a+b): (b+c): (c+a)= 6:7:8 and sum of the numbers a,b,c is 14, then the value of c is

Answer 1

Answer:

If (a+b):(b+c):(c+a) = 6:7:8 and (a+b+c) = 14, what is the value of C?

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(a+b)=6k

(b+c)=7k

(c+a)=8k

Now, we get addition of LHS & RHS

2a+2b+2c=21k

2(a+b+c)=21k

2(14)=21k —————- [given - (a+b+c)=14]

28=21k

k=28/21=4/3 ———————(1)

Since,

a+b+c=14

c=14-(a+b)

we have,

a+b=6k

a+b=6(4/3) ——————-from 1

a+b=8

now,

c=14-(a+b)

c=14–8

c=6