Question

if a/b=b/c=c/d then prove that pa^3+qb^3+rc^3/pb^3+qc^3+rd^3 = a/d​

Answer 1

Answer:

a,b,c,d are in continued proportion

=> a/b = b/c = c/d = k

=> a = bk

b = ck

c = dk

a = (ck)k = dk * k * k

=> a/d = k³

(a - b)/(b -c) = (bk - b)/(ck - c)

= b(k -1)/c(k - 1)

= b/c

= k

= a/d = ((a - b)/(b -c))³

a : d = ( (a-b):(b-c) )³

Answer 2

Answer:

tq for free points

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