if a/b=b/c then prove that: abc(a³-b³-c³) = (a³b³-b³c³-c³a³)
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Step-by-step explanation:
a/b=b/c
ac=b²
b²b(a³-b³-c³)or b³(a³-b³-c³)
abc(a³-b³-c³)=a³b³-b⁶-b³c³
as we formulated from above equation that b²=ac
b⁶=(b²)³
(b²)³=(ac)³
b⁶=a³c³
hence abc(a³-b³-c³)=a³b³-b³c³-a³c³
hope you got it
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