Math, asked by negendranepal123, 10 months ago

if a/b=b/c then prove that: abc(a³-b³-c³) = (a³b³-b³c³-c³a³)

Answers

Answered by priyankapriyanka1980
2

Step-by-step explanation:

a/b=b/c

ac=b²

b²b(a³-b³-c³)or b³(a³-b³-c³)

abc(a³-b³-c³)=a³b³-b⁶-b³c³

as we formulated from above equation that b²=ac

b⁶=(b²)³

(b²)³=(ac)³

b⁶=a³c³

hence abc(a³-b³-c³)=a³b³-b³c³-a³c³

hope you got it

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