Question

if a/b=b/c, then the value of 1/b-c + 1/b-a is​

Answer 1

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Answer 2

Answer:

1/b

first step

normal addition

i.e.,b-a+b-c/(b-c)(b-a)

which is equal to 2b-a-c/b^2-b(c+a)+ca

WKT a/b=b/c

so ac=b^2

now we sustitute ca byb^2

so

2b-a-c/b^2-b(c+a)+b^2

so b^2+b^2=2b^2

now take out - in the numerator