Question

if a b + BC + CA equals to zero find the value of one upon a square minus b c plus one upon B square minus C plus one upon C square minus A B

Answer 1

if ab + bc + ca = 0, then find 1/a 2 -bc +...

If ab + bc + ca = 0, then find

1/a2-bc + 1/b2 – ca + 1/c2- ab

3 years ago

Answers : (2)

Hello student,
Please find the answer to your question below
Given ab+bc+ca=0 and asked to find value 1/(a2-bc ) + 1/(c2-ab) + 1/(a2-bc)
Put -ac = ab + bc ; -ab = ac+ bc and -bc =ab + ac
you get :
=(1/(a2+ab+ac))+(1/(c2+ac+bc))+(1/(a2+ab+ac))
=(1/a(a+b+c))+(1/b(a+b+c))+(1/c(a+b+c))
By taking LCM we get
=(ab + bc + ca)/[(a+b+c)(abc)]
put, ab+bc+ca=0
you get value = 0/[(a+b+c)(abc)] = 0

Take a=b=1 and get the value of c , so you will get c=-1/2.

put the value of a=b=1 and c=-1/2 in the equation on the right hand side , you will get ans as 0.

Answer 2

Answer:

See the answer below