Question

if a b + bc + ca is abc then find the value of a+b/ab(c-1)+b+c/bc(a-1)+c+a/ca(b-1)

Answer 1

Answer:

Here is your Answer

Step-by-step explanation:

1/a + 1/b + 1/c=3

(ab + bc + ac)/abc = 3

Multiply both sides by a + b + c

(a + b + c)(ab + bc + ac)/abc = 1 x 3

(a²b + abc + a²c + ab² + b²c + abc + abc + bc² + ac²)/abc = 1 x 3

(a²b + ab² + b²c + bc² + a²c + ac² + 3abc)/abc = 3

(ab(a+b) + bc(b+c) + ac(a+c) + 3abc)/abc = 3

ab(a+b) + bc(b+c) + ac(a+c) + 3abc = 3abc

ab(a+b) + bc(b+c) + ac(a+c) = 0