Question

if a b + BC + CA is equal to 10 a square + b square + c square is 44 find a cube plus b cube plus c cube - 3abc​

Answer 1

Answer:

ans is 2176

Step-by-step explanation:

ATQ

ab+bc+ca=10 ,a^2+b^2+c^2=44

a^3+b^3+c^3=?

(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca

=44+2(ab+bc+ca)

=44+2(10)=44+20=64

a^3+b^3+c^3-3abc

=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

=(64) {44-(ab+bc+ca)}

=(64) (44-10)

=(64 ) (34)

=2176

Answer 2

Answer:

(a+b+c)^2=44+2(10)=64

a+b+c=8

a^3+b^3+c^3-3abc=8(44-10)=8(34)=272