If a+b+c=0,a cube+b cube +c cube =
Answers
Answered by
1
a + b + c = 0
=> a + b = - c ------(1)
On cubing both sides, we get
( a + b)^3 = (-c)^3
=> a^3 + b^3 + 3ab (a + b) = - c^3
=> a^3 + b^3 + 3ab ( - c) = - c^3
=> a^3 + b^3 - 3abc = - c^3
=> a^3 + b^3 + c^3 = 3abc
=> a + b = - c ------(1)
On cubing both sides, we get
( a + b)^3 = (-c)^3
=> a^3 + b^3 + 3ab (a + b) = - c^3
=> a^3 + b^3 + 3ab ( - c) = - c^3
=> a^3 + b^3 - 3abc = - c^3
=> a^3 + b^3 + c^3 = 3abc
Answered by
0
a + b + c = 0
=> a + b = - c ------(1)
On cubing both sides, we get
( a + b)^3 = (-c)^3
=> a^3 + b^3 + 3ab (a + b) = - c^3
=> a^3 + b^3 + 3ab ( - c) = - c^3
=> a^3 + b^3 - 3abc = - c^3
=> a^3 + b^3 + c^3 = 3abc
Similar questions